Infinity x 0 = 1

[yugi9999]

it really does.....a number x0 = 0 but infinity goes on forever so it equals 1

[gigglechris2]

while your proof itself is all correct (im nerdy like that) infinity x 0 is NOT 1; this is due to the imperfections in human designed math, and, in fact; the imperfections in humans, human's functions, human's thoughts, human's creations, and anything that is human, related to humans, affected by humans, made by humans, used by humans etc. is imperfect so as it seems the human numerical/math system is also imperfect as we see here

[Archer]

Jul 8, 2009 20:56:11 GMT gigglechris2 said:

while your proof itself is all correct (im nerdy like that) infinity x 0 is NOT 1; this is due to the imperfections in human designed math, and, in fact; the imperfections in humans, human's functions, human's thoughts, human's creations, and anything that is human, related to humans, affected by humans, made by humans, used by humans etc. is imperfect so as it seems the human numerical/math system is also imperfect as we see here

We all know that.Remember that nothing can be perfect unless created by God.These people contributed to us by making these systems and all.Plus they have been used for a long, long time.We are just discussing if the theory is right, following human made mathematic laws.

[gigglechris2]

well.... yes and no; because in human mathematical laws they say that infinity is never ending; and if it was 1 it would end; and because of this infinity x 0= infinity because infinity keeps on going and it cannot be stopped at 0... so again it isnt 1 but it isnt 0 either...

[godslaw75]

Infinity is not a "real" number and cannot be used in arithmetic calculations, so you cannot perform operations like infinity * n, + n, - n, /n and expect to get a real number

IE:
Let n be any number.
Infinity * n = infinity
n = (infinity * n) / infinity


"Infinity” in of itself is not defined in either the real number field nor the complex number field and so neither statement makes any sense in them:

(1/infinity) = 0
is a false statement

Infinity x 0 = 1
this is false too
this because 0 is unconditionally zero, real or complex or hell even imagined

[Archer]

Thing is we're talking bout infinity.Infinity, a word that scientist and mathematicians came up with to define a sum which goes on forever and is no longer in range of human or computer calculation.Which means infinity doesn't really have a value but it is infinity as we know it is, a sum that goes on forever.

So we say this : -

∞ x 0 =1

and you say it's wrong but can you prove that?I mean think this : -

∞ x 0 =2 or ∞ x 0 =3 or ∞ x 0 =4

could that be the answer??No, right and no one can really come up with a 'real' answer.So they probably decided that ∞ x 0 = 1 is the best decision/answer.

[godslaw75]

Fine
In the context of measure theory, it is usual to take 0 × ∞ to be 0. obtained in the context of limits, if you set the limit of the subexpressions using L'Hôpital's rule ie

That limit could converge to any number, or diverge to infinity, or might not exist, depending on what the functions f and g are.

The condition is :
Lim f(x)=0
x->c
while
Lim g(x)= ∞
x->c

the translation of 0 × ∞ to L'Hôpital's rule of 0/0

Lim f(x)g(x)
x->c
=
Lim f(x) / (1/g(x))
x->c

so to simplify

0/(1/∞) = 0


You have zeroed an infinite number multiple times which is zero or you have infinity dividing an infinite number of zeros which is zero.

lastly as an Any number multiplied by zero will always equal zero therefore the absolute value of 0 is 0

[yugi9999]

You All Got Me A Little Confused xD

[godslaw75]

Advance math can be a bit Confusing.

[Archer]

Yes, you're right there.The limitation is right but as x->∞, y->0 so that's one of the reasons why.

Because x x y = z or translated ∞ x 0 = 1.

[godslaw75]

AS I said before under Measure Theory math where you would use 0 × infinity, it is usual to take 0 × infinity to be = to 0

[some1hackme]

y cant it be 0? im so confused after this

[some1hackme]

Why bother stressing yourself out from this?